(1/9)^x=81^x+4

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Solution for (1/9)^x=81^x+4 equation: 



(1/9)^x=81^x+4

We move all terms to the left:

(1/9)^x-(81^x+4)=0



Domain of the equation: 9)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/9)^x-(81^x+4)=0

We get rid of parentheses

(+1/9)^x-81^x-4=0

We multiply all the terms by the denominator


(+1-81^x*9)^x-4*9)^x=0

Wy multiply elements

(+1-81^x*9)^x-36x=0

We add all the numbers together, and all the variables

-36x+(+1-81^x*9)^x=0

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